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Complete the truth table and determine whether or not the following statement is a tautology, a contradiction, or neither.

$\mathbin{\sim} ( \mathbin{\sim} p\wedge q)\wedge (p\vee q)$

$p$	$q$	$\mathbin{\sim} p\wedge q$	$\mathbin{\sim} ( \mathbin{\sim} p\wedge q)$	$p\vee q$	$\mathbin{\sim} ( \mathbin{\sim} p\wedge q)\wedge (p\vee q)$
T	T
T	F
F	T
F	F

The statement is a
A. Contradiction, because the statement is always false
B. Tautology, because the statement is always false
C. Tautology, because the statement is always true
D. Contradiction, because the statement is always true
E. Neither